Medium
Given an array of integers nums containing n + 1 integers where each integer is in the range [1, n] inclusive.
There is only one repeated number in nums, return this repeated number.
You must solve the problem without modifying the array nums and uses only constant extra space.
Example 1:
Input: nums = [1,3,4,2,2]
Output: 2
Example 2:
Input: nums = [3,1,3,4,2]
Output: 3
Example 3:
Input: nums = [1,1]
Output: 1
Example 4:
Input: nums = [1,1,2]
Output: 1
Constraints:
1 <= n <= 105nums.length == n + 11 <= nums[i] <= nnums appear only once except for precisely one integer which appears two or more times.Follow up:
nums?from typing import List
class Solution:
def findDuplicate(self, nums: List[int]) -> int:
arr = [0] * (len(nums) + 1)
for num in nums:
arr[num] += 1
if arr[num] == 2:
return num
return 0